From 6b836cd4dce50fc61b4c116331f9ed6b06c7ba19 Mon Sep 17 00:00:00 2001
From: fmgoncharov <83536185+fmgoncharov@users.noreply.github.com>
Date: Thu, 17 Jun 2021 19:26:16 +0300
Subject: [PATCH] Update lecture25.tex
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Забыт штрих
---
 Lectures/lecture25.tex | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Lectures/lecture25.tex b/Lectures/lecture25.tex
index 92d2ba2..b246edd 100644
--- a/Lectures/lecture25.tex
+++ b/Lectures/lecture25.tex
@@ -379,7 +379,7 @@ \subsection{Метод Якоби}
 Пусть $B_k'$ будет матрица $\beta$ в штрихованном базисе.
 Тогда $B_{k+1} = C^t B_{k+1}' C$, а значит 
 \[
-\Delta_{k+1} = \det B_{k+1}  = \det B_{k+1}' \det C^2 = \det B_{k+1} = \beta(e_1',e_1')\ldots \beta(e_{k+1}',e_{k+1}')
+\Delta_{k+1} = \det B_{k+1}  = \det B_{k+1}' \det C^2 = \det B_{k+1}' = \beta(e_1',e_1')\ldots \beta(e_{k+1}',e_{k+1}')
 \]
 Что доказывает оставшееся равенство.
 \end{proof}