-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathexamp.tex
More file actions
163 lines (134 loc) · 4.34 KB
/
examp.tex
File metadata and controls
163 lines (134 loc) · 4.34 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
\documentclass{beamer}
\mode<presentation>
\usepackage{amsmath}
\usepackage{amssymb}
%\usepackage{advdate}
\usepackage{adjustbox}
\usepackage{subcaption}
\usepackage{enumitem}
\usepackage{multicol}
\usepackage{listings}
\usepackage{gensymb}
\usepackage{url}
\usepackage{gensymb}
\def\UrlBreaks{\do\/\do-}
\usetheme{Boadilla}
\usecolortheme{lily}
\setbeamertemplate{footline}
{
\leavevmode%
\hbox{%
\begin{beamercolorbox}[wd=\paperwidth,ht=2.25ex,dp=1ex,mathright]{author in head/foot}%
\insertframenumber{} / \inserttotalframenumber\hspace*{2ex}
\end{beamercolorbox}}%
\vskip0pt%
}
\setbeamertemplate{navigation symbols}{}
\providecommand{\nCr}[2]{\,^{#1}C_{#2}} % nCr
\providecommand{\nPr}[2]{\,^{#1}P_{#2}} % nPr
\providecommand{\mbf}{\mathbf}
\providecommand{\pr}[1]{\ensuremath{\Pr\mathmathleft(#1\mathmathright)}}
\providecommand{\qfunc}[1]{\ensuremath{Q\mathleft(#1\mathright)}}
\providecommand{\sbrak}[1]{\ensuremath{{}\mathleft[#1\mathright]}}
\providecommand{\lsbrak}[1]{\ensuremath{{}\mathleft[#1\mathright.}}
\providecommand{\rsbrak}[1]{\ensuremath{{}\mathleft.#1\mathright]}}
\providecommand{\brak}[1]{\ensuremath{\mathleft(#1\mathright)}}
\providecommand{\lbrak}[1]{\ensuremath{\mathleft(#1\mathright.}}
\providecommand{\rbrak}[1]{\ensuremath{\mathleft.#1\mathright)}}
\providecommand{\cbrak}[1]{\ensuremath{\mathleft\{#1\mathright\}}}
\providecommand{\lcbrak}[1]{\ensuremath{\mathleft\{#1\mathright.}}
\providecommand{\rcbrak}[1]{\ensuremath{\mathleft.#1\mathright\}}}
\theoremstyle{remark}
\newtheorem{rem}{Remark}
\newcommand{\sgn}{\mathop{\mathrm{sgn}}}
\providecommand{\abs}[1]{\mathleft\vert#1\mathright\vert}
\providecommand{\res}[1]{\Res\displaylimits_{#1}}
\providecommand{\norm}[1]{\lVert#1\rVert}
\providecommand{\mtx}[1]{\mathbf{#1}}
\providecommand{\mean}[1]{E\mathleft[ #1 \mathright]}
\providecommand{\fourier}{\overset{\mathcal{F}}{ \mathrightmathleftharpoons}}
%\providecommand{\hilbert}{\overset{\mathcal{H}}{ \mathrightmathleftharpoons}}
\providecommand{\system}{\overset{\mathcal{H}}{ \longmathleftmathrightarrow}}
%\newcommand{\solution}[2]{\textbf{Solution:}{#1}}
%\newcommand{\solution}{\noindent \textbf{Solution: }}
\providecommand{\dec}[2]{\ensuremath{\overset{#1}{\underset{#2}{\gtrless}}}}
\newcommand{\myvec}[1]{\ensuremath{\begin{pmatrix}#1\end{pmatrix}}}
\let\vec\mathbf
\lstset{
%language=C,
frame=single,
breaklines=true,
columns=fullflexible
}
\numberwithin{equation}{section}
\title{\LARGE {\bf POWER ELECTRONICS}}
\author{{Sai Manasa Pappu EE17BTECH11036}\\ { Sahir Bansal EE17BTECH11035}}
\date{\today}
\begin{document}
\begin{frame}
\titlepage
\end{frame}
\begin{frame}
\frametitle{Problem Statement}
Python script to find the output of the 4th order low pass filter, with input as obtained from result of 3.1.
\bigbreak
\end{frame}
%\subsection{Literature}
\section{Solution}
\subsection{Centre}
\begin{frame}
\frametitle{Filter Response}
%\framesubtitle{Literature}
\bigbreak
\bigbreak
\bigbreak
Fourth order low pass filter cutoff frequency = 50 Hz. Note that this frequency is same as the input frequency.
\bigbreak
Hence input will be attenuated by 3dB.
\begin{align}
%\vec{x}^T\vec{x}-2\vec{O}^T\vec{x} +F = 0
V_{out} (peak) = \frac{1}{\sqrt{2}}V_{in} (peak)
\end{align}
%
Phase at f = 50 Hz is 4 x -45{\degree} = -180\degree
\begin{align}
\angle H(f) = -180 \degree
\end{align}
We can also verify the same by plotting magnitude and phase response of the filter in python.
\end{frame}
\begin{frame}
\begin{figure}
\frametitle{Magnitude Response}
\includegraphics[width=1\columnwidth ]{magnitude.png}
\label{magnitude.png}
\end{figure}
\end{frame}
\begin{frame}
\frametitle{Phase Response}
\begin{figure}
\centering
\includegraphics[width=1\columnwidth ]{phase.png}
\end{figure}
\end{frame}
\begin{frame}{}
\frametitle{Output}
Hence output frequency will be same as input frequency, peak voltage reduces by a factor of ${\sqrt{2}}$ and is out of phase with input.
\bigbreak
\begin{align}
V_{out} = \frac{1}{\sqrt{2}} V_{in} \angle 180 \degree
\end{align}
\begin{align}
V_{out} = -0.707V_{m}sin(wt)
\end{align}
\end{frame}
\begin{frame}
\frametitle{Output}
\begin{figure}
\centering
\includegraphics[width=1\columnwidth ]{out.png}
\end{figure}
\end{frame}
\begin{frame}{Github Link for Python Code }
\url{https://github.com/SaiManasaPappu/Digital-Communication/blob/master/3.5.py}
\end{frame}
\end{document}