Looking in the class I found the calculation for temperature is wrong
Celsius and Kelvin are lineal proportional
0K = -273.15 C
So is a simple sum
K + 273.15 = C
C - 273.15 = K
on FAHRENHEIT is different because is no lineal like Kelvin
(1.80 * C) + 32 = F
(F - 32) / 1.8 = C1
For kelvin only need to convert C or from C:
(1.80 * (K-273.15) ) + 32 = F
((F - 32) / 1.8 ) + 273.15 = K
Looking in the class I found the calculation for temperature is wrong
Celsius and Kelvin are lineal proportional
0K = -273.15 C
So is a simple sum
K + 273.15 = C
C - 273.15 = K
on FAHRENHEIT is different because is no lineal like Kelvin
(1.80 * C) + 32 = F
(F - 32) / 1.8 = C1
For kelvin only need to convert C or from C:
(1.80 * (K-273.15) ) + 32 = F
((F - 32) / 1.8 ) + 273.15 = K