Error if bower dependencies are empty

[Horttcore]

It might be pointless, but it would be good if there won't be an error if there are no dependencies in the bower.json.

Here is an example from my gulpfile.

 *
 * Task: Scripts
 *
 * - Sourcemap
 * - Combine
 * - Concat
 * - Minify
 * - Sync browsers
 *
 */
gulp.task('scripts', function() {
	var filterJS = plugins.filter(['**/*.js','!jquery.fancybox.pack.js']); // Broken by fancy
	return gulp.src(mainBowerFiles({
		    paths: {
		        bowerDirectory: 'src/bower_components',
		        bowerrc: '.bowerrc',
		        bowerJson: 'bower.json'
		    },
		}))
		.pipe(filterJS)
		.pipe(plugins.addSrc.append('src/scripts/plugins/*.js'))
		.pipe(plugins.addSrc.append('src/scripts/*.js'))
		.pipe(plugins.plumber({errorHandler: plugins.notify.onError("Error: <%= error.message %>")}))
		.pipe(plugins.sourcemaps.init())
		.pipe(plugins.concat('scripts.combined.js'))
		.pipe(gulp.dest('dist/scripts'))
		.pipe(plugins.rename({suffix: '.min'}))
		.pipe(plugins.uglify())
		.pipe(plugins.sourcemaps.write('./'))
		.pipe(gulp.dest('dist/scripts'))
		.pipe(plugins.notify("Scripts updated"))
		.pipe(browserSync.stream());
});

[ck86]

Why would you use it if you don't have dependencies?

[Horttcore]

By default I have a lightbox and slider script. But sometimes I need none of them, so returning an empty array wouldn't block the rest of my default build script.

This is more like error preventing.

[ck86]

I don't get the point. You use the same gulp task for every project? When do you have the dependencies and when not?