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lucky_numbers.cpp
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122 lines (95 loc) · 2.97 KB
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// https://www.hackerrank.com/challenges/lucky-numbers
#include <iostream>
using namespace std;
typedef unsigned long long LL;
const int MAX_LENGTH = 18, MAX_SUM = 162, MAX_SQUARE_SUM = 1458;
int primes[1460], start[19][163], end[19][163];
LL dyn_table[20][164][1460];
LL ans[19][10][164][1460];
void get_primes() {
for (int i = 0; i <= MAX_SQUARE_SUM; ++i)
primes[i] = 1;
primes[0] = primes[1] = 0;
for (int i = 2; i * i <= MAX_SQUARE_SUM; ++i) {
if (!primes[i]) continue;
for (int j = 2; i * j <= MAX_SQUARE_SUM; ++j)
primes[i*j] = 0;
}
}
void get_table() {
for (int i = 0; i <= MAX_LENGTH; i++) {
for (int j = 0; j <= MAX_SUM; j++) {
for (int k = 0; k <= MAX_SQUARE_SUM; k++) {
dyn_table[i][j][k] = 0;
}
}
}
dyn_table[0][0][0] = 1;
for (int i = 0; i < MAX_LENGTH; i++)
for (int j = 0; j <= 9 * i; j++)
for (int k = 0; k <= 9 * 9 * i; k++)
for (int l = 0; l < 10; ++l)
dyn_table[i + 1][j + l][k + l*l] += dyn_table[i][j][k];
}
LL count_lucky (LL maxp) {
LL result = 0, step_result, step;
int len = 0, split_max[MAX_LENGTH], sum = 0, sq_sum = 0;
while (maxp) {
split_max[len] = maxp % 10;
maxp /= 10;
len++;
}
for (int i = len-1; i >= 0; i--) {
step_result = 0;
int x1 = 9 * i;
for (int l = 0; l < split_max[i]; l++) {
int x = l*l + sq_sum, y = l + sum;
step = 0;
if(ans[i][l][sum][sq_sum] != 0) {
step_result +=ans[i][l][sum][sq_sum];
continue;
}
for (int j = 0; j <= x1; j++) {
if(primes[j + y])
for (int k = start[i][j]; k <= end[i][j]; k++) {
if (primes[k + x]) {
step_result += dyn_table[i][j][k];
step += dyn_table[i][j][k];
}
}
}
ans[i][l][sum][sq_sum] = step;
}
result += step_result;
sum += split_max[i];
sq_sum += split_max[i] * split_max[i];
}
if (primes[sum] && primes[sq_sum]) result++;
return result;
}
int main() {
get_primes();
get_table();
for(int i = 0; i <= 18; i++)
for(int j = 0;j <= 163; j++) {
for(int k = 0; k <= 1458; k++)
if(dyn_table[i][j][k] != 0ll) {
start[i][j] = k;
break;
}
for(int k = 1460; k >= 0; k--)
if(dyn_table[i][j][k] != 0ll) {
end[i][j]=k;
break;
}
}
int cases = 0;
cin >> cases;
for (int i = 0; i < cases; i++) {
LL a, b;
cin >> a >> b;
if(b == 1000000000000000000ll) b--;
cout << count_lucky(b) - count_lucky(a-1) << endl;
}
return 0;
}