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153.py
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32 lines (31 loc) · 1.12 KB
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class Solution(object):
def findMin(self, nums):
"""
:type nums: List[int]
:rtype: int
总共4中情况,然后可以合并的。
"""
i, j = 0, len(nums)-1
while i < j:
mid = (i+j)/2
if nums[i] < nums[mid] < nums[j]: # 如果是升序数组
return nums[i]
elif nums[j] < nums[mid] < nums[i]: # 如果是降序数组
return nums[j]
elif nums[mid] < nums[j] < nums[i]: # 正常情况1
j = mid
elif nums[mid] > nums[i] > nums[j]: # 正常情况2
i = mid
elif nums[mid] == nums[i] or nums[mid] == nums[j]: # i j相邻,必为其中之一
return nums[i] if nums[i] < nums[j] else nums[j]
return nums[i]
def findMin(self, nums):
# 更加concise的写法
i, j = 0, len(nums)-1
while i < j-1: # a useful trick
mid = i + (j-i) / 2
if nums[mid] < nums[j]:
j = mid
else:
i = mid
return nums[i] if nums[i] < nums[j] else nums[j]