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import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashSet;
import java.util.List;
import java.util.Set;
/**
* Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the
* candidate numbers sums to T.
*
* Each number in C may only be used once in the combination.
*
* Note:
* All numbers (including target) will be positive integers.
* Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
* The solution set must not contain duplicate combinations.
* For example, given candidate set 10,1,2,7,6,1,5 and target 8,
* A solution set is:
* [1, 7]
* [1, 2, 5]
* [2, 6]
* [1, 1, 6]
* @author joshluo
*/
public class CombinationSum2 {
public List<List<Integer>> combinationSum2(int[] candidates, int target) {
assert (candidates.length > 0 && target > 0);
// Process the array and create a new set holding all candidates
Arrays.sort(candidates);
// calculate all combinations
Set<List<Integer>> combinations = new HashSet<List<Integer>>();
List<Integer> combination = new ArrayList<Integer>();
int startIndex = 0;
getCombinations(candidates, target, startIndex, combination, combinations);
return new ArrayList<List<Integer>>(combinations);
}
private void getCombinations(final int[] candidates, final int target, final int startIndex,
final List<Integer> combination, final Set<List<Integer>> combinations) {
if (target > 0) {
for (int i = startIndex; i < candidates.length; i++) {
if (target - candidates[i] < 0) {
return;
}
combination.add(candidates[i]);
getCombinations(candidates, target - candidates[i], i + 1, combination, combinations);
combination.remove(combination.size() - 1);
}
} else {
combinations.add(new ArrayList<Integer>(combination));
}
}
public static void main(String[] args) {
CombinationSum2 combinationSum2 = new CombinationSum2();
int[] candidates = { 10, 1, 2, 7, 6, 1, 5 };
int target = 8;
System.out.println(combinationSum2.combinationSum2(candidates, target));
}
}