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Prob0.java
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54 lines (46 loc) · 1.47 KB
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package techgig;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
/*
* To find the maximum sum from a list/array without considering consecutive numbers
*/
public class Prob0 {
public static int maxSum(List<Integer> list) {
int max = 0;
if(list.size() == 0) {
return 0;
} else if(list.size() == 1) {
return list.get(0);
} else if(list.size() == 2) {
return Math.max(list.get(0), list.get(1));
} else if(list.size() == 3) {
int z = list.get(0), o = list.get(1), t = list.get(2);
return Math.max(Math.max(Math.max(z, t), (z + t)), o);
}
else if(list.size() > 3) {
int sum;
for(int i = 0; i < list.size(); i++) {
if(i == 0) {
sum = list.get(i) + maxSum(list.subList(i + 2, list.size()));
} else if(i == list.size() - 1) {
sum = list.get(i) + maxSum(list.subList(0, list.size() - 2));
} else if(i == 1) {
sum = list.get(i) + /*maxSum(Collections.<Integer> emptyList()) +*/ maxSum(list.subList(i + 2, list.size()));
} else if(i == list.size() - 2) {
sum = list.get(i) + maxSum(list.subList(0, i - 1)) /*+ maxSum(Collections.<Integer> emptyList())*/;
} else {
sum = list.get(i) + maxSum(list.subList(0, i - 1)) + maxSum(list.subList(i + 2, list.size()));
}
if(sum > max) {
max = sum;
}
}
}
return max;
}
public static void main(String[] args) {
List<Integer> list = Arrays.asList(100,50,50,100);
System.out.println("Max Sum is = " + maxSum(list));
}
}