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Problem018_Maximum_path_sum_I.py
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87 lines (87 loc) · 2.37 KB
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# -*- coding: utf-8 -*-
# Problem 018 Maximum path sum I
#By starting at the top of the triangle below and moving to adjacent numbers
# on the row below, the maximum total from top to bottom is 23.
#
#3
#7 4
#2 4 6
#8 5 9 3
#
#That is, 3 + 7 + 4 + 9 = 23.
#
#Find the maximum total from top to bottom of the triangle below:
#
# 75
# 95 64
# 17 47 82
# 18 35 87 10
# 20 04 82 47 65
# 19 01 23 75 03 34
# 88 02 77 73 07 63 67
# 99 65 04 28 06 16 70 92
# 41 41 26 56 83 40 80 70 33
# 41 48 72 33 47 32 37 16 94 29
# 53 71 44 65 25 43 91 52 97 51 14
# 70 11 33 28 77 73 17 78 39 68 17 57
# 91 71 52 38 17 14 91 43 58 50 27 29 48
# 63 66 04 68 89 53 67 30 73 16 69 87 40 31
#04 62 98 27 23 09 70 98 73 93 38 53 60 04 23
#
#NOTE: As there are only 16384 routes, it is possible to solve this problem
#by trying every route. However, Problem 67, is the same challenge with a
#triangle containing one-hundred rows; it cannot be solved by brute force,
# and requires a clever method! ;o)
# 75, 95, 17, 18, 4, 1, 2, 4, 26, 33, 65, 28, 17, 53, 9
import time
start=time.time()
###########################
L=[ [75],
[95,64],
[17,47,82],
[18,35,87,10],
[20,4,82,47,65],
[19,1,23,75,3,34],
[88,2,77,73,7,63,67],
[99,65,4,28,6,16,70,92],
[41,41,26,56,83,40,80,70,33],
[41,48,72,33,47,32,37,16,94,29],
[53,71,44,65,25,43,91,52,97,51,14],
[70,11,33,28,77,73,17,78,39,68,17,57],
[91,71,52,38,17,14,91,43,58,50,27,29,48],
[63,66,4,68,89,53,67,30,73,16,69,87,40,31],
[4,62,98,27,23,9,70,98,73,93,38,53,60,4,23] ]
Lbis=[]
for i in range(len(L)) :
Lbis.append([])
for j in range(len(L[i])) :
Lbis[i].append(L[i][j])
i = len(L)-1
R=[]
while i>0 :
i=i-1
Rbis=[]
for j in range(len(L[i])) :
if Lbis[i+1][j] > Lbis[i+1][j+1] :
Rbis.append(j)
Lbis[i][j]=Lbis[i][j]+Lbis[i+1][j]
else :
Rbis.append(j+1)
Lbis[i][j]=Lbis[i][j]+Lbis[i+1][j+1]
R.insert(0,Rbis)
reponse = Lbis[0][0]
print(reponse)
# pour avoir la chaine :
#j = 0
#nbr = 0
#chaine = []
#chaine.append(L[j][nbr])
#while j < len(R) :
# nbr = R[j][nbr]
# j = j + 1
# chaine.append(L[j][nbr])
#print(chaine)
##########################
#temps pour trouver la réponse :
end=time.time()
print(f"temps pour trouver la réponse : {end-start}")