socket.sendall() throws Broken Pipe on second write attempt

[butlern]

If the remote side of your connection goes away, this means that the first write to the socket after the connection goes away is LOST.

To replicate, run netcat -lk 4242

Then in a python shell (instantiate your socket and connect to it. Before the first sendall, Ctrl-C your netcat server):

>>> import socket
>>> s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
>>> s.settimeout(2)
>>> s.connect(('localhost', 4242))
>>> s.sendall('\n'.encode('utf8'))
>>> s.sendall('\n'.encode('utf8'))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)
socket.error: [Errno 32] Broken pipe

Not sure if there is a socket flag to avoid this. A hack would be to just s.sendall('\n'.encode('utf8') first before attempting to actually writing data.

[butlern]

I should note this was tested on python 2.7 on OS X and Ubuntu