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largestBSTinBTJava
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51 lines (46 loc) · 1.7 KB
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class NodeValue {
public int maxNode, minNode, maxSize;
NodeValue(int minNode, int maxNode, int maxSize) {
this.maxNode = maxNode;
this.minNode = minNode;
this.maxSize = maxSize;
}
};
class Solution {
private NodeValue largestBSTSubtreeHelper(TreeNode root) {
// An empty tree is a BST of size 0.
if (root == null) {
return new NodeValue(Integer.MAX_VALUE, Integer.MIN_VALUE, 0);
}
// Get values from left and right subtree of current tree.
NodeValue left = largestBSTSubtreeHelper(root.left);
NodeValue right = largestBSTSubtreeHelper(root.right);
// Current node is greater than max in left AND smaller than min in right, it is a BST.
if (left.maxNode < root.val && root.val < right.minNode) {
// It is a BST.
return new NodeValue(Math.min(root.val, left.minNode), Math.max(root.val, right.maxNode),
left.maxSize + right.maxSize + 1);
}
// Otherwise, return [-inf, inf] so that parent can't be valid BST
return new NodeValue(Integer.MIN_VALUE, Integer.MAX_VALUE,
Math.max(left.maxSize, right.maxSize));
}
public int largestBSTSubtree(TreeNode root) {
return largestBSTSubtreeHelper(root).maxSize;
}
}