strfront.py

#Given a string and a non-negative int n, we'll say that the front of the string is the first 3 chars, or whatever is there if the string is less than length 3. Return n copies of the front; 
#front_times('Chocolate', 2) - 'ChoCho'
#front_times('Chocolate', 3) - 'ChoChoCho'
#front_times('Abc', 3) - 'AbcAbcAbc'
def front_times(str,counter):
    substr=str[:3]
    restr=''
    for num in range(0,counter):
        restr=restr+substr
    print restr+"\n"

front_times("Chocolate",2)
front_times("Chocolate",3)
front_times("Abc",3)