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Hrošč 1 #2

@petermlakar

Description

@petermlakar

V primeru, ko v povratni funkciji kanala 0 zaženemo novo nit, ki pošlje sporočilo na kanal 1, se izvajanje ustavi po nedoločenem času (v primeru, ko na kanal 0 pride velika količina zaporednih sporočil).

Prejemnik:

import time
import _thread
from echolib import pyecho

class P0():

    def __init__(self):
        self.loop = pyecho.IOLoop()
        self.client = pyecho.Client()
        self.loop.add_handler(self.client)

        self.input =  pyecho.Subscriber(self.client, "input",  "int", self.callback)
        self.output = pyecho.Publisher(self.client,  "output", "int")

    def callback(self, message):
        print(pyecho.MessageReader(message).readInt())

        _thread.start_new_thread(self.send, ())

    def send(self):
        w = pyecho.MessageWriter()
        w.writeInt(1)

        self.output.send(w)

def main():

    p = P0()

    try:
        while p.loop.wait(10):
            time.sleep(0.001)
    except KeyboardInterrupt:
        pass



if __name__ == "__main__":
    main()

Pošiljatelj:

import time
import _thread
from echolib import pyecho

class P1():

    def __init__(self):
        self.loop = pyecho.IOLoop()
        self.client = pyecho.Client()
        self.loop.add_handler(self.client)

        self.output =  pyecho.Publisher(self.client, "input",  "int")

def main():

    p = P1()
    c = 0

    try:
        while p.loop.wait(10):
            w = pyecho.MessageWriter()
            w.writeInt(c)
            c += 1

            p.output.send(w)

            time.sleep(0.001)
    except KeyboardInterrupt:
        pass



if __name__ == "__main__":
    main()

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