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26 changes: 26 additions & 0 deletions 0503/Programmers/Lv1/Lv1_noh.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
class Solution {
public int[] solution(int[] lottos, int[] win_nums) {
int[] answer = {};
answer = new int[2];

int zero = 0;
int same = 0;
for (int i = 0; i < lottos.length; ++i) {
if (lottos[i] == 0) {
++zero;
continue;
}
for (int j = 0; j < win_nums.length; ++j) {
if (lottos[i] == win_nums[j]) {
++same;
break;
}
}
}

answer[0] = 7 - (same + zero == 0 ? 1 : same + zero);
answer[1] = 7 - (same == 0 ? 1 : same);

return answer;
}
}
56 changes: 56 additions & 0 deletions 0503/Programmers/Lv2/Lv2_noh.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,56 @@
import java.util.Arrays;

class Solution {
public String[] solution(String[] files) {
String[] answer = {};

Arrays.sort(files, (o1, o2) -> {
// 스트링으로 변환
String str1 = o1;
String str2 = o2;

// 소문자로 바꿔서 비교
str1 = str1.toLowerCase();
str2 = str2.toLowerCase();

// str1의 넘버의 시작과 끝 인덱스 찾기
int idx1 = -1;// 시작 인덱스
int idx2 = -1;// 끝 인덱스
for (int i = 0; i < str1.length(); ++i)
if ('0' <= str1.charAt(i) && str1.charAt(i) <= '9') {
if (idx1 == -1) {
idx1 = i;
idx2 = i;
} else if (idx2 == i - 1)
idx2 = i;
}
// str1을 찾은 인덱스로 나누기
String head1 = str1.substring(0, idx1);
String number1 = str1.substring(idx1, idx2 + 1);

// str2도 마찬가지로 진행
idx1 = -1;
idx2 = -1;
for (int i = 0; i < str2.length(); ++i)
if ('0' <= str2.charAt(i) && str2.charAt(i) <= '9') {
if (idx1 == -1) {
idx1 = i;
idx2 = i;
} else if (idx2 == i - 1)
idx2 = i;
}
String head2 = str2.substring(0, idx1);
String number2 = str2.substring(idx1, idx2 + 1);

// 헤드가 같으면 넘버로 비교
if (head1.equals(head2)) {
return Integer.parseInt(number1) - Integer.parseInt(number2);
}
// 헤드가 다르면 헤드로 비교
return head1.compareTo(head2);
});

answer = files;
return answer;
}
}