Treat a non-finite select bound as an open side - #885
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`CoordRange._get_index` divides by the step and, when the result is not finite, took that as a zero step. Two things reach that branch: a zero step, whose samples all equal start, and a non-finite bound, which has no index because it means an open side. Reading the second as the first produced a backwards slice, so `patch.select(distance=(50, np.inf))` raised `ValueError: __len__() should return >= 0`. Against the last release the same call silently returned an empty patch: v0.1.20 resolved the bound through `np.floor(inf).astype(np.int64)`, which is `INT64_MIN`, and clamped to nothing. Tested at both levels, since the branch was already exercised by the zero step case it was written for and the regression still got through.
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In `@dascore/core/coords.py`:
- Around line 1653-1659: Update the index calculation around the non-finite
fraction branch to distinguish non-finite input bounds from arithmetic overflow:
validate whether the bound value is finite before computing the fraction,
treating non-finite bounds as open sides while mapping overflow from finite
bounds to the appropriate out-of-range index. Preserve the zero-step handling in
_get_zero_step_index.
In `@tests/test_proc/test_proc_coords.py`:
- Around line 295-301: Update tests/test_proc/test_proc_coords.py lines 295-301
in test_select_infinite_bound to use an interior distance bound and verify
distance=(bound, np.inf) trims the patch. Update tests/test_core/test_coords.py
lines 1441-1448 to use an interior coordinate bound and assert both returned
slices contain only the expected partial range.
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dascore/core/coords.pytests/test_core/test_coords.pytests/test_proc/test_proc_coords.py
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| # bound (np.inf, NaN) has none; it means an open side. | ||
| if step == 0: | ||
| return self._get_zero_step_index(value, forward) | ||
| return None |
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When a finite bound is many orders of magnitude larger than a small nonzero step, (value - start) / step can overflow to infinity even though value itself is finite. For example, CoordRange(start=0.0, stop=1e-305, step=1e-308).select((1e308, None)) now treats the lower bound as open and returns the whole coordinate instead of an empty selection; a very negative finite upper bound has the analogous problem. Distinguish a genuinely non-finite input bound from a non-finite computed fraction before returning None.
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Same finding as CodeRabbit's on this line, and fixed the same way in 4ba52c6 — see that thread for the detail. Reproduced with your example: CoordRange(start=0.0, stop=1e-305, step=1e-308).select((1e308, None)) returned the whole 1000-sample coord instead of nothing.
Rather than test the bound for finiteness — awkward for the datetime and timedelta coords which share this path, where math.isfinite raises and NaT is the only non-finite value — the branch uses the sign of the fraction, which gives the same answer for a genuine infinity and an overflowed finite bound: an upper bound past the last sample is an open side, a lower bound past it selects nothing.
Two reviewers on the same line is worth the weight; thank you.
| if step == 0: | ||
| return self._get_zero_step_index(value, forward) | ||
| return None |
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When the infinite bound is represented as a zero-dimensional NumPy array, such as coord.select((50, np.array(np.inf))), ndarray satisfies Sized, so execution bypasses this new scalar non-finite branch and enters the array path below. That path still casts infinity to the minimum int64 value, causing the selection to be empty rather than treating the bound as open, so the reported failure remains for a scalar-like input representation that the coordinate code otherwise accepts.
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Confirmed and fixed in 4ba52c6. Measured before the fix, on a 0-100 coord:
scalar inf : slice(50, None, None) # open, correct
0-d array : slice(0, 0, None) # empty
_get_index now unboxes a 0d array and re-enters the scalar path, so one bound written as an array means what it means written bare. That also fixes a smaller oddity next door: a finite 0d bound produced slice(50, array([81])), an array where an index belongs.
Test: test_select_non_finite_bound_in_0d_array.
| # start, has a degenerate but defined index. A non-finite | ||
| # bound (np.inf, NaN) has none; it means an open side. |
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This introduces np.inf as a user-visible spelling for an open select bound, but neither the public Patch.select docstring nor docs/tutorial/patch.qmd mentions it; the tutorial still documents only ... for open intervals. Add the new bound semantics to the public API documentation or the relevant .qmd, as repository guidance requires documentation for every behavior or API change. .agents/agents.mdL43-L46
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Fixed in 4ba52c6. select_values_description in dascore/constants.py is the shared block behind Patch.select, Spool.select, and their unselect counterparts, so documenting it there states it once for every method that takes these values:
Noneand ... both indicate open intervals, as does an infinite bound pointing away from the data, eg(min, np.inf).
docs/tutorial/patch.qmd says the same, and gained None while I was there — it documented only ....
The qualification is load-bearing rather than hedging: an infinite bound is an open side on the side it points, so (np.inf, 50) is empty rather than everything. See this thread.
Reviewers pointed out that a finite bound can also make the fraction non-finite: `(value - start) / step` overflows when the two are far enough apart, and reading that as an open side selects everything when the bound asked for nothing. The sign settles both cases without asking where the infinity came from. An infinite fraction is a bound past one end of the coord, and which end it is decides the answer: an upper bound above every sample is the same as no upper bound, while a lower bound above every sample selects nothing. That is what the range checks below already say, so the branch only has to name the end. NaN keeps its own line, since it names no end at all. Also unbox a 0d array, which is Sized and so took the array path, where an infinite bound was cast to the smallest int64 and the selection came back empty.
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`_get_compatible_value` reads a null bound — NaN and NaT alike — as None and returns before the division, so a NaN fraction only ever comes from a zero step, which the line above already answers. Codecov is what noticed: the branch was the one new line no test covered, and no test could.
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Two things from working these findings which are worth stating on the PR rather than in a thread. A NaN bound never reaches the branch that was written for it. A timedelta step compared to a bare |
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Description
patch.select(distance=(50, np.inf))raises ondev:CoordRange._get_indexcomputesfraction = (value - start) / stepand, when the result is not finite, treats that as a step of zero. Two different things land there:start, so the index is degenerate but defined;np.inf,NaN), which has no index at all because it means an open side.#790 gave the first case a defined index — correctly — and routed the second there too.
_get_zero_step_index(inf, forward=False)returns0, so(50, inf)becameslice(50, 0), a backwards slice whose negative length surfaced from__len__.Only the upper bound broke.
-np.infon the lower side survived because0happens to be the right answer there, which is why it went unnoticed.Against the last release
v0.1.20 did not raise, but it did not work either. It resolved the bound through the array path, where
np.floor(np.inf).astype(np.int64)isINT64_MIN, so the slice clamped to nothing and the call silently returned an empty patch. The documented open-bound spellings,...andNone, were correct throughout. So the user-visible change in this release is silently-empty to correct, which is what the changelog entry below states.Tests
At the coordinate level,
np.infandNaNbounds must agree with...; at the patch level, the reported call must agree withselect(distance=(dmin, ...)). Both, because #790 shipped with a test for the zero-step input its new branch was written for, and nothing covered the input that was already flowing through that branch — coverage went up while a working case broke.Each side of the contract is pinned against a bound in the middle of the coordinate, so a test cannot pass by ignoring the finite side as well as the infinite one.
Which end an infinity names
An infinite fraction is not always an infinite bound:
(value - start) / stepoverflows for a finite bound far enough fromstart, which is a bound outside the coord rather than an open side. Both are settled by the sign, without asking where the infinity came from — an upper bound above every sample is the same as no upper bound, while a lower bound above every sample selects nothing, which is what the existing range checks already say. So(50, np.inf)is open, and the inverted spelling(np.inf, 50)is empty rather than everything. NaN keeps its own branch, since it names no end at all.Changelog
...andNone.patch.select(distance=(50, np.inf))silently returned an empty patch, because an infinite bound resolved toINT64_MINas an index.Checklist
I have:
docs/contributing/general_guidelines.qmd).I have (if applicable):
Summary by CodeRabbit
Bug Fixes
NaNbounds so they are correctly treated as open-ended limits.Tests
NaN, and ellipsis-based selections.