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104. Maximum Depth of Binary Tree #20
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,11 @@ | ||
| ### step1 | ||
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| わからなかったのでChatGPTに解いてもらった。DFSで左右のnodeのうち深い方を取って+1していくことを繰り返すだけだった。 | ||
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| ### step2 | ||
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| 変更点なし。 | ||
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| ### step3 | ||
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| 3回通すまで書き直し。 | ||
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,13 @@ | ||
| class Solution { | ||
| public: | ||
| int maxDepth(TreeNode* root) { | ||
| if (root == nullptr) { | ||
| return 0; | ||
| } | ||
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| int leftDepth = maxDepth(root->leftNode); | ||
| int rightDepth = maxDepth(root->rightNode); | ||
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| return max(leftDepth, rightDepth) + 1; | ||
| } | ||
| }; |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,13 @@ | ||
| class Solution { | ||
| public: | ||
| int maxDepth(TreeNode* root) { | ||
| if (root == nullptr) { | ||
| return 0; | ||
| } | ||
|
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| int leftDepth = maxDepth(root->leftNode); | ||
| int rightDepth = maxDepth(root->rightNode); | ||
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| return max(leftDepth, rightDepth) + 1; | ||
| } | ||
| }; |
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,13 @@ | ||
| class Solution { | ||
| public: | ||
| int maxDepth(TreeNode* root) { | ||
| if (root == nullptr) { | ||
| return 0; | ||
| } | ||
|
|
||
| int leftDepth = maxDepth(root->leftNode); | ||
| int rightDepth = maxDepth(root->rightNode); | ||
|
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| return max(leftDepth, rightDepth) + 1; | ||
| } | ||
| }; |
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他のC++で取り組まれた方達のPR/レビューもいくつか見てみると有意義だと思います。
どんなふうに考えているかとか、どんなアルゴリズムを使っているかなど、勉強になります。
ただ、その分時間はかかるので、負担にならない程度にくらいです。
(私の場合、自分で取り組んだ時間よりも長く時間を使うことが多いので、見るべきポイントを絞っていたりしています。)
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そうですね、ほかの方のPRやレビューも確認するようにします!