⚡ Replace O(N^2) dictionary deep equality check with O(N) lookup - #3
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The generated code for deep equality of dictionaries loops over all values of `rhsDictionary` for each key in `lhsDictionary`, causing an O(N^2) time complexity. By looking up the value using `rhsDictionary[lhsKey]`, this drops to O(N). Co-authored-by: esenmx <43244505+esenmx@users.noreply.github.com>
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💡 What: Replaced the nested loop O(N^2) iteration over both dictionaries in
deepEqualswith an O(N) direct key lookup.🎯 Why: Deep equality checks for dictionaries should not perform an O(N^2) loop when dictionary lookups provide an O(1) retrieval. For larger dictionaries, this optimization eliminates significant overhead.
📊 Measured Improvement: The change fundamentally alters the algorithm from O(N^2) to O(N). We could not easily benchmark the exact Pigeon-generated Swift file in the limited container environment, but a direct equivalent test on dictionaries demonstrated normal hash map access speed scaling linearly with elements rather than quadratically. Since
messages.g.swiftis generated code, an identical fix needs to be submitted upstream to thepigeonpackage. This fix directly patches the plugin codebase to realize the performance gain immediately.PR created automatically by Jules for task 4892462123730500124 started by @esenmx