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Solution #2266

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realeksit Jun 4, 2026
4c769bf
Move dict cache inside the wrapper function
realeksit Jun 4, 2026
cdc770c
Return cached back to outer func. Add kwargs to cache key too
realeksit Jun 4, 2026
2f2a5d4
flake8 error solved
realeksit Jun 4, 2026
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17 changes: 14 additions & 3 deletions app/main.py
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Original file line number Diff line number Diff line change
@@ -1,6 +1,17 @@
from typing import Callable
from functools import wraps
from typing import Any, Callable


def cache(func: Callable) -> Callable:
# Write your code here
pass
cached = {}

@wraps(func)
def wrapper(*args, **kwargs) -> Any:
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@mateacademy-ai-mentor mateacademy-ai-mentor Jun 4, 2026

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The kwargs parameter is accepted but never used in the cache key. If someone calls the decorated function with keyword arguments like func(a=1, b=2), the cache won't recognize it as the same call as func(1, 2). Either include kwargs in the cache key or document that keyword arguments are not supported.

key = (args, frozenset(kwargs.items()))
if cached.get(key, None) is None:
cached[key] = func(*args, **kwargs)
print("Calculating new result")
else:
print("Getting from cache")
return cached[key]
return wrapper
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